{"id":814,"date":"2018-11-03T03:30:00","date_gmt":"2018-11-03T03:30:00","guid":{"rendered":"https:\/\/robertjwallace.com\/\/\/?p=814"},"modified":"2020-07-07T19:46:25","modified_gmt":"2020-07-07T19:46:25","slug":"aces-and-dice","status":"publish","type":"post","link":"https:\/\/robertjwallace.com\/es\/aces-and-dice\/","title":{"rendered":"Ases y dados"},"content":{"rendered":"
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Efecto:<\/h2>\nEl artista baraja dos veces una baraja y la coloca sobre la mesa. Luego, muestra cuatro dados. El espectador tira los dados para obtener cuatro n\u00fameros aleatorios. El artista toma la baraja, muestra las cartas superior e inferior y reparte cuatro montones de cartas. El n\u00famero de cartas repartidas en cada mont\u00f3n corresponde al n\u00famero de cada dado. Por ejemplo, si los dados muestran un 4, un 3, un 5 y un 3, el primer mont\u00f3n tendr\u00e1 4 cartas, el segundo 3, el tercero 5 y el cuarto 3. Al girar la carta superior de cada mont\u00f3n, se revelan los cuatro ases.\n\nThe main sleight used for this is a second deal.\n\n<\/div>\n<\/div>\n
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Method:<\/h2>\nStart with the aces in the positions from the top of the deck of 5el<\/sup>, 7el<\/sup>, 13el<\/sup> and 15el<\/sup>. The deck can be preset or the aces can be culled to the top of the deck and the cards stacked into position with two shuffles described later. Note that if the deck is preset you can perform any false shuffle that keeps the top 15 cards intact.\n\nWith the aces in the correct position there are many combinations of dice rolls that let you deal out the piles to end with the aces. The trick is in the order the dice are arranged, and the use of a second deal when required.\n\nThe first ace is at position 5el<\/sup> from the top. So if a five is rolled then it can be used to deal the first pile. But even a four can be used by using a second deal on the fourth card. Likewise if a six is rolled then a second deal on the fifth card places an ace as the last card dealt.\n\nOnce the first pile is dealt, the second ace, which was at position 7el<\/sup> from the top to begin with will now be either on top (if the first pile has six cards), second (if the first pile has five cards), or third (if the pile has four cards.)\n\nSo for the second pile the die is a little more tricky. A simple way to figure out what the first two die can be is to make sure they add up to seven. For example, a six for the first and a one for the second, or a five and two, or a four and three. In all of these cases you can easily arrive at an ace on top of each of the first two piles with only a couple of second deals. The best case of a five and two have no second deals. If the first two dice add up to seven, then after the two piles are dealt, the remaining two aces are at positions 6el<\/sup> and 8el<\/sup> from the top of the remaining deck.\n\nBelow are tables showing the deals with the letter \u201cT\u201d for dealing a top, and the letter \u201cS\u201d for dealing a second.\n\n<\/div>\n<\/div>\n
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\n<\/colgroup>\n\n\n\n\n\n\n\n\n\n\n\n\n
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Two die adding to 7<\/p>\n<\/th>\n<\/tr>\n<\/thead>\n

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4<\/p>\n<\/th>\n

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3<\/p>\n<\/th>\n

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5<\/p>\n<\/th>\n

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2<\/p>\n<\/th>\n

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6<\/p>\n<\/th>\n

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1<\/p>\n<\/th>\n<\/tr>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n<\/tr>\n

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T<\/p>\n<\/td>\n

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S<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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S<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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S<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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Positions of the last two aces after making the first two piles<\/p>\n<\/td>\n<\/tr>\n

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6<\/p>\n<\/td>\n

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8<\/p>\n<\/td>\n

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6<\/p>\n<\/td>\n

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6<\/p>\n<\/td>\n

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6<\/p>\n<\/td>\n

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8<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<\/div>\n

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The first two dice can also add up to either a six or an eight.\n<\/colgroup>\n\n\n\n\n\n\n\n\n\n\n\n\n
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Two die adding to 6<\/p>\n<\/th>\n

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Two die adding to 8<\/p>\n<\/th>\n<\/tr>\n<\/thead>\n

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4<\/p>\n<\/th>\n

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2<\/p>\n<\/th>\n

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5<\/p>\n<\/th>\n

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1<\/p>\n<\/th>\n

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6<\/p>\n<\/th>\n

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2<\/p>\n<\/th>\n

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5<\/p>\n<\/th>\n

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3<\/p>\n<\/th>\n

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4<\/p>\n<\/th>\n

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4<\/p>\n<\/th>\n<\/tr>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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S<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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S<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n<\/tr>\n

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T<\/p>\n<\/td>\n

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S<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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S<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n<\/tr>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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S<\/p>\n<\/td>\n<\/tr>\n

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S<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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S<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n<\/tr>\n

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T<\/p>\n<\/td>\n

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S<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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T<\/p>\n<\/td>\n

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Positions of the last two aces after making the first two piles<\/p>\n<\/td>\n<\/tr>\n

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6<\/p>\n<\/td>\n

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8<\/p>\n<\/td>\n

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7<\/p>\n<\/td>\n

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9<\/p>\n<\/td>\n

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5<\/p>\n<\/td>\n

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7<\/p>\n<\/td>\n

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5<\/p>\n<\/td>\n

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7<\/p>\n<\/td>\n

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5<\/p>\n<\/td>\n

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7<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<\/div>\n

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So in the case of the first dice adding to 8, then the remaining aces are now at the 5el<\/sup> and 7el<\/sup> positions. In the case of the first two dice adding to 6, the remaining dice end up either in positions 6 and 8 (as in the case of the dice adding to 7) or, positions 7 and 9.\n

Case of last two aces at 6el<\/sup> and 8th<\/h3>\nNow lets look at the last two dice. Since four of the above scenerios end up with the remaining aces at the 6el<\/sup> and 8el<\/sup> position lets look at that case first.\n\nTo get to the 6el<\/sup> card you need either a 5 or a 6 spot rolled. In the case of a 6 spot, you simply deal down to the ace. The last ace is then second from the top and you can use any spot value to reach it with using seconds.\n\nIf the die is a 5 spot then you deal four down and then a second. This leaves the last ace third from the top, so in that case you can use any die value except the one spot.\n\nSo looking at all the cases of the third and fourth aces ending up 6el<\/sup> and 8el<\/sup> from the top here are some die combinations that work:\n